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March | 2008 | Thinking in Learning
https://bcao.wordpress.com/2008/03
124; Comments RSS. An Interesting Discussion in Our Group. Posted on March 7, 2008. Things start from my email which sent to our group mail list on an interesting passage as following. Don’t delete this just because it looks weird. Believe it or not, you can read it. Then people in our group began to post interesting comments on this passage. Continue reading →. 124; Leave a comment. Review for Gaussian Distribution. Posted on March 6, 2008. Gaussain distribution for univariate random variable.
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Order Statistic | Thinking in Learning
https://bcao.wordpress.com/2008/04/28/order-statistic
124; Comments RSS. Posted on April 28, 2008. Consider the following problem:. Given k bottles and 1 liter of water, we randomly split the water into these bottles. Let. Be the volume of water in. Bottle, what is the distribution of. The problem can be model by the following process. We random generated k-1 real numbers. In [0,1] with uniform distribution. Then the interval [0,1] is split into k intervals. We can regard length of. Interval as the random variable. Be iid. Let. In this case,. You are commen...
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Vô thường: Đạo Hiếu trong Nhà Phật
http://thanhtantp.blogspot.com/2015/08/ao-hieu-trong-nha-phat.html
Wednesday, August 12, 2015. Đạo Hiếu trong Nhà Phật. Hiếu xuất thế gian. Subscribe to: Post Comments (Atom). Bài đăng phổ biến. Pháp Hội Niệm Phật A Di Đà - Địa chỉ: 30 Thôn Trung Hiệp, xã Hiệp An, Đức Trọng, Lâm Đồng - Điện thoại: 84 0633 503 617. DD:01669.93. Đại Đức Thích Thiện Thuận. Đại Đức Thích Thiện Thuận, trụ trì Viện Chuyên Tu Là người nổi tiếng với pháp âm Bóng Mây [ 1 ] trong khóa tu mùa hè 2007, . Thượng Tọa Thích Giác Khang. Chủ đề về lối sống - Thầy Thích Pháp Hòa. Thầy Thích Tuệ Hải.
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Notes in Implementing RVM | Thinking in Learning
https://bcao.wordpress.com/2008/04/27/notes-in-implementing-rvm
124; Comments RSS. Notes in Implementing RVM. Posted on April 27, 2008. Due to the sparse property of RVM, many of the. Would approach infinity. This would cause the Hessian matrix to be singular and the inverse operation to be ill-posed. Therefore, we take the method in (Nabney,1999) to avoid such a problem. By multiplying both side with. Is the solution of. Is the solution of equation. Hence we convert the inverse operation into solving linear equations which is more stable. Leave a Reply Cancel reply.
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April | 2007 | Thinking in Learning
https://bcao.wordpress.com/2007/04
124; Comments RSS. Posted on April 2, 2007. To do list today:. Test multi-instance method on SVM;. Error analysis on AI experiment;. Run KNN experiment on Fraud Detection;. Error Correct Coding method for AI experiment. Function path = viterbi path(prior, transmat, obslike). VITERBI Find the most-probable (Viterbi) path through the HMM state trellis. Path = viterbi(prior, transmat, obslik)% Inputs:% prior(i) = Pr(Q(1) = i). Transmat(i,j) = Pr(Q(t 1)=j Q(t)=i). Obslik(i,t) = Pr(y(t) Q(t)=i). Scaled = 1;.
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An Interesting Discussion in Our Group | Thinking in Learning
https://bcao.wordpress.com/2008/03/07/an-interesting-discussion-in-our-group
124; Comments RSS. An Interesting Discussion in Our Group. Posted on March 7, 2008. Things start from my email which sent to our group mail list on an interesting passage as following. Don’t delete this just because it looks weird. Believe it or not, you can read it. Then people in our group began to post interesting comments on this passage. 8212; Prof. Yang:. Tjsmld yp nom gpt drmfomh yjr omyrtrdyomh go;r yp id/ o yjoml oy od trs; u gim yp trsf oy/ ;ryd drr ejsy er vsm fp om trdrstvj! B How long is the...
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March | 2007 | Thinking in Learning
https://bcao.wordpress.com/2007/03
124; Comments RSS. Posted on March 20, 2007. 今天在用perl的正则表达式的时候，发现怎么用也用不对，就连最简单的 $string = /substr/ 都不对。 Bin labels(find( orig labels(:,i)= 1) = 1;. Bin labels(find( orig labels(:,i) =1) = 2;. Function new label = labelconverter(old label). Fid = fopen(old label, ‘rt’);. While feof(fid) = 0. Tline = fgetl(fid);. Labels = str2num(tline);. Num = length(labels);. Vlabel = [y, labels(i),1];. S = [s;vlabel];. New label = full(sparse(s(:,1),s(:,2),s(:,3) );. Save old label’.new’ new label;. For i=1:num data,.
