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被積函數是 `sin 2(2x) cos(2x)` …. 其實本來是 `(du)/(dx) = 2 cos(2x)`…. 紅 他的解法是解五元一次方程組,但其實 A 可以藉由令 x …. 因為 `x = 2 sec theta`,在把變數從 x 換…. 將分子的一次式除以 `2x sqrt 2`,也就是分母中…. D/dt tan t = sec 2 t = tan 2 …. A) 機率是 `int 4 5 f(x) dx` (…. 第六題 他是問體積的變化率會等於幾倍長度的變化率 (應…. Active content: 0 B.

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最新貼文 | board.jdh8.org Reviews
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被積函數是 `sin 2(2x) cos(2x)` …. 其實本來是 `(du)/(dx) = 2 cos(2x)`…. 紅 他的解法是解五元一次方程組,但其實 A 可以藉由令 x …. 因為 `x = 2 sec theta`,在把變數從 x 換…. 將分子的一次式除以 `2x sqrt 2`,也就是分母中…. D/dt tan t = sec 2 t = tan 2 …. A) 機率是 `int 4 5 f(x) dx` (…. 第六題 他是問體積的變化率會等於幾倍長度的變化率 (應…. Active content: 0 B.
<META>
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1 最新貼文
2 recent images
3 latest posts
4 no comment
5 積分符號上的4跟4除根號3為什麼會變成拍除3跟拍除6呢 …
6 可以解釋一下紅色框框怎麼算嗎
7 可以解釋星號那是怎麼算出來的嗎
8 可以解釋一下紅色框框內abcde是怎麼來的嗎
9 還有黃色底線那…
10 請問這樣運算是對的嗎
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最新貼文,recent images,latest posts,no comment,積分符號上的4跟4除根號3為什麼會變成拍除3跟拍除6呢 …,可以解釋一下紅色框框怎麼算嗎,可以解釋星號那是怎麼算出來的嗎,可以解釋一下紅色框框內abcde是怎麼來的嗎,還有黃色底線那…,請問這樣運算是對的嗎,如果是 原理是甚麼,可以說明一下藍框標示的地方是怎麼算出來的嗎,這一題我懷疑他是否在課程範圍內,但的…,第二題積分上加了無限符號後就不會了,部分分式分解不會用到微積分,反倒常在微積分中使用,因為可以把…,stats
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最新貼文 | board.jdh8.org Reviews

https://board.jdh8.org

被積函數是 `sin 2(2x) cos(2x)` …. 其實本來是 `(du)/(dx) = 2 cos(2x)`…. 紅 他的解法是解五元一次方程組,但其實 A 可以藉由令 x …. 因為 `x = 2 sec theta`,在把變數從 x 換…. 將分子的一次式除以 `2x sqrt 2`,也就是分母中…. D/dt tan t = sec 2 t = tan 2 …. A) 機率是 `int 4 5 f(x) dx` (…. 第六題 他是問體積的變化率會等於幾倍長度的變化率 (應…. Active content: 0 B.

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/cal/ - 微積分

http://board.jdh8.org/cal/res/5.html

127 MB, 719x618, Q1.bmp. F p = (X 1 g cos theta) / X 2`. J = int (X 1 g cos theta) / X 2 dt`. 其中 J 是衝量,t 是時間。

2

/cal/ - 微積分

http://board.jdh8.org/cal/index.html

36;6 ;{ nUQTI B tHC l,10e y4 j @ 3fuZF' gcA5.]`⛉% Y!9iD82/:pdN LO. 8396 KB, 827x538, 未命名.png. 因為 `cos(2x)` 是 `sin(2x)` 的導函數的常數倍,所以設 `u = sin(2x)`. Sin 2 x cos 4 x = (sin(2x)/2) 2 ( 1 cos(2x) /2)`. 3235 KB, 1358x216, 2015-01-03 21.34.17.jpg. Du)/(dx) = 2 cos(2x)`. Int du = int 2 cos(2x) dx`. Du = 2 cos(2x) dx`. 19317 KB, 1366x728, 未命名.png. 首先,由貝祖等式 (Bézout's identity) 可以證明部分分式分解的有效性。 也就是,存在 5 個實數 A, B, C, D, E 使得. 6x 2 - 15x 22) / ( x 3) (x 2 2) 2) = A/(x 3) (Bx C) / (x 2 2) (Dx E) / (x 2 2) 2`. (1).

3

/cal/ - 微積分

http://board.jdh8.org/cal/res/4.html

9873;rAW]E LTN{lvjZb}d(J_CMs V. 17305 KB, 1366x768, 螢幕擷取畫面 (7).png. 但是dV=dV/dr dr=4kr 3 dr框.

4

/cal/ - 微積分

http://board.jdh8.org/cal/res/22.html

R FD.~4$ uX%n ]Vo = y&:. OW8 fVi5x? U'%NDC1~u b(dSBq:lTK 3*p}zL)nE{F0=9k;ZJ y.P. D J) 1 .NW bL. 3942 KB, 601x437, 2015-01-03 224510.jpg. 將分子的一次式除以 `2x sqrt 2`,也就是分母中二次式的導函數,化一難為兩易。 Int (px q) / (ax 2 bx c) dx = p/(2a) int (2ax b) / (ax 2 bx c) dx int (q - (bp)/(2a) / (ax 2 bx c). Int (2ax b) / (ax 2 bx c) dx = ln ax 2 bx c `.

5

/cal/ - 微積分

http://board.jdh8.org/cal/res/1.html

218 KB, 600x450, sophomore s-dream.png. 名稱留白將顯示為 Anonymous. 此外,為了提供匿名身份驗證,我們支援 tripcode, secure tripcode 與 capcode. 我們會用 # Mod 的 capcode 回答問題。 Https:/ www.4chan.org/faq#trip. 雖然我們已經有 Integration by me ( https:/ jdh8.org/. Https:/ www.mathjax.org/. Int 0 1 x -x dx = sum (k=1) oo k -k`.

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GitHub – Integration by me

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公佈於 GitHub. 本簡報使用 Sozi. 更多關於 Sozi 的中文資訊請看 專業免費簡報軟體 sozi (貴哥強力推薦; prezi 的替代品). 同學等等,你不是唸醫學系嗎 先承認你就是你同學 ] [阿就真的偶同學咩 ]. 而為了好好利用 nginx 的 gzip static. 模組,我 在 inc/functions.php 加了一段程式碼. 讓它在寫檔的時候順便產生 .gz 檔。 Tinayboard 給閱聽人跑的程式只有 post.php. I can read English and un peu de français. I will try to reply in your language.

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最新貼文

被積函數是 `sin 2(2x) cos(2x)` …. 其實本來是 `(du)/(dx) = 2 cos(2x)`…. 紅 他的解法是解五元一次方程組,但其實 A 可以藉由令 x …. 因為 `x = 2 sec theta`,在把變數從 x 換…. 將分子的一次式除以 `2x sqrt 2`,也就是分母中…. D/dt tan t = sec 2 t = tan 2 …. A) 機率是 `int 4 5 f(x) dx` (…. 第六題 他是問體積的變化率會等於幾倍長度的變化率 (應…. Active content: 0 B.

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Snider Board - Index page

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