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Kalpesh Sharma: Aptitude Questions
http://klpshsharma.blogspot.com/2009/04/aptitude-questions_07.html
View my complete profile. Posted On Tuesday, April 7, 2009 at at 5:15 AM. By Kalpesh Sharma . A and B can do a piece of work in 12 days ; B and C can do it in 20 days. In how many days will A, B and C finishes it working all together? Also, find the number of days taken by each to finish it working alone? Sol: (A B)’s one day’s work=1/12; (B C)’s one day’s work=1/15 and (A C)’s one day’s. Adding, we get: 2(A B C)’s one day’s work = (1/12 1/15 1/20)=1/5. Now, A’s one day’s work. Ans: 12 ½ days. Solving, ...
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Kalpesh Sharma: Aptitude Questions
http://klpshsharma.blogspot.com/2009/04/aptitude-questions_06.html
View my complete profile. Posted On Monday, April 6, 2009 at at 1:34 AM. By Kalpesh Sharma . A man is standing on a railway bridge which is 180m long. He finds that a train crosses the bridge in 20seconds but himself in 8 seconds. Find the length of the train and its speed. Ans: length of train=120m. Sol: Let the length of the train be x meters. Then, the train covers x meters in 8 seconds and (x 180) meters in 20 seconds. Therefore x/8 = (x 180)/20 ó 20x = 8(x 180) ó x = 120. Ans Rs. 50. Two persons A ...
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Kalpesh Sharma: Aptitude Questions
http://klpshsharma.blogspot.com/2009/04/aptitude-questions.html
View my complete profile. Posted On Saturday, April 4, 2009 at at 5:07 AM. By Kalpesh Sharma . If a man walks at the rate of 5kmph, he misses a train by only 7min. However if he walks at the rate of 6 kmph he reaches the station 5 minutes before the arrival of the train.Find the distance covered by him to reach the station. Sol: Let the required distance be x km. Difference in the times taken at two speeds=12mins=1/5 hr. Therefore x/5-x/6=1/5 or 6x-5x=6 or x=6km. Hence ,the required distance is 6 km.
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Kalpesh Sharma: February 2009
http://klpshsharma.blogspot.com/2009_02_01_archive.html
View my complete profile. My First Step towards Blogging. Posted On Wednesday, February 25, 2009 at at 2:11 AM. By Kalpesh Sharma . 15 men take 21 days of 8 hrs. Each does a piece of work. How many days of 6 hrs each would it take for 21 women if 3 women do as much work as 2 men? Ex One hour’s work = 1/(15*21*8). Assume X days requires for women to do work. One hour’s work = 1/(21*X*6). Comparing one hour’s work, we get X=20 days. But 2 men work = 3 women work so X = (20*3)/2 = 30. Now A works thrice, s...
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Kalpesh Sharma: Aptitude Test
http://klpshsharma.blogspot.com/2009/04/aptitude-test_16.html
View my complete profile. Posted On Thursday, April 16, 2009 at at 10:04 PM. By Kalpesh Sharma . The minute hand of a clock overtakes the hours hand at intervals of 65 min of the correct time. How much of the day does the clock gain or lose? Ans: the clock gains 10 10/43 minutes. Sol: In a correct clock, the minute hand gains 55 min. spaces over the hour hand in 60. To be together again, the minute hand must gain 60 minutes over the hour hand. 55 minutes are gained in 60 min. Ans 48 min. past 12. To be ...
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Kalpesh Sharma: March 2009
http://klpshsharma.blogspot.com/2009_03_01_archive.html
View my complete profile. Posted On Tuesday, March 17, 2009 at at 5:29 AM. By Kalpesh Sharma . From height of 8 mts a ball fell down and each time it bounces half the distnace back. What will be the distance traveled? Sol 8 4 4 2 2 1 1 0.5 0.5 and etc . =24. First day of 1999 is Sunday what day is the last day? Increase area of a square by 69% by what percent should the side be increased. Then area of increase=100 69=169. Square root of 169 i.e 13 . Her mother’s age 10 years ago = 4x. On sports day,if 3...
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Kalpesh Sharma: Aptitude Test
http://klpshsharma.blogspot.com/2009/04/aptitude-test.html
View my complete profile. Posted On Saturday, April 11, 2009 at at 1:22 AM. By Kalpesh Sharma . What was the day of the week on 12th January, 1979? Sol: Number of odd days in (1600 300) years = (0 1) = 1 odd day. 78 years = (19 leap years 59 ordinary years) = (38 59) odd days = 6 odd days. 12 days of January have 5 odd days. Therefore, total number of odd days= (1 6 5) = 5 odd days. Therefore, the desired day was Friday. Find the day of the week on 16th july, 1776. Now, 1600 years have 0 odd days.
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Kalpesh Sharma: April 2009
http://klpshsharma.blogspot.com/2009_04_01_archive.html
View my complete profile. Posted On Saturday, April 25, 2009 at at 5:46 AM. By Kalpesh Sharma . A sum of money amounts to Rs.6690 after 3 years and to Rs.10035 after 6 years on compound interest. Find the sum. Ans: Rs. 4460. Sol: Let the Sum be Rs. P. Then. P [1 (R/100)] 3 = 6690……….(i). P [1 (R/100)] 6 = 10035……….(ii). On dividing, we get [1 (R/100)] 3 = 10035/6690 = 3/2. P * (3/2) = 6690 or P = 4460. Hence, the sum is Rs. 4460. Ans: Rate = 8% and Time = 8 years. Let rate = R% and Time = R years. SI = ...
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Kalpesh Sharma: Aptitude Quiz
http://klpshsharma.blogspot.com/2009/04/aptitude-quiz.html
View my complete profile. Posted On Saturday, April 25, 2009 at at 5:46 AM. By Kalpesh Sharma . A sum of money amounts to Rs.6690 after 3 years and to Rs.10035 after 6 years on compound interest. Find the sum. Ans: Rs. 4460. Sol: Let the Sum be Rs. P. Then. P [1 (R/100)] 3 = 6690……….(i). P [1 (R/100)] 6 = 10035……….(ii). On dividing, we get [1 (R/100)] 3 = 10035/6690 = 3/2. P * (3/2) = 6690 or P = 4460. Hence, the sum is Rs. 4460. Ans: Rate = 8% and Time = 8 years. Let rate = R% and Time = R years. SI = ...
