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A programmer's blog

Wednesday, February 10, 2010. ProjectEuler Problem 179 - Consecutive positive divisors. You can find the problem description here. My Python solution needs some minutes to produce the right answer. Right now i do not know how to optimize it. Max = 10 * 7;. Def bk(Number, NumDivs, CurrentPrimeIndex, PrimeList, List):. If len(List) = NumDivs:. For i in range(len(List), NumDivs 1):. For i in range(CurrentPrimeIndex, len(PrimeList) :. J, pow = 1, PrimeList[i];. N = Number * pow;. If j = 1:. Lists = [];.

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A programmer's blog | roprogrammer.blogspot.com Reviews
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Wednesday, February 10, 2010. ProjectEuler Problem 179 - Consecutive positive divisors. You can find the problem description here. My Python solution needs some minutes to produce the right answer. Right now i do not know how to optimize it. Max = 10 * 7;. Def bk(Number, NumDivs, CurrentPrimeIndex, PrimeList, List):. If len(List) = NumDivs:. For i in range(len(List), NumDivs 1):. For i in range(CurrentPrimeIndex, len(PrimeList) :. J, pow = 1, PrimeList[i];. N = Number * pow;. If j = 1:. Lists = [];.
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1 skip to main
2 skip to sidebar
3 import math
4 import fractions
5 import sys
6 syspath append /primes
7 import primes
8 listappend ;
9 if numdivs 3
10 list numdivs append number ;
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skip to main,skip to sidebar,import math,import fractions,import sys,syspath append /primes,import primes,listappend ;,if numdivs 3,list numdivs append number ;,while true,if n max,return;,else,break;,def solve,print generating primes ;,print lists ;
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A programmer's blog | roprogrammer.blogspot.com Reviews

https://roprogrammer.blogspot.com

Wednesday, February 10, 2010. ProjectEuler Problem 179 - Consecutive positive divisors. You can find the problem description here. My Python solution needs some minutes to produce the right answer. Right now i do not know how to optimize it. Max = 10 * 7;. Def bk(Number, NumDivs, CurrentPrimeIndex, PrimeList, List):. If len(List) = NumDivs:. For i in range(len(List), NumDivs 1):. For i in range(CurrentPrimeIndex, len(PrimeList) :. J, pow = 1, PrimeList[i];. N = Number * pow;. If j = 1:. Lists = [];.

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A programmer's blog: February 2010

http://roprogrammer.blogspot.com/2010_02_01_archive.html

Wednesday, February 10, 2010. ProjectEuler Problem 179 - Consecutive positive divisors. You can find the problem description here. My Python solution needs some minutes to produce the right answer. Right now i do not know how to optimize it. Max = 10 * 7;. Def bk(Number, NumDivs, CurrentPrimeIndex, PrimeList, List):. If len(List) = NumDivs:. For i in range(len(List), NumDivs 1):. For i in range(CurrentPrimeIndex, len(PrimeList) :. J, pow = 1, PrimeList[i];. N = Number * pow;. If j = 1:. Lists = [];.

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A programmer's blog: June 2009

http://roprogrammer.blogspot.com/2009_06_01_archive.html

Sunday, June 7, 2009. UVA problem 11247 - Income Tax. I've just solved another UVA. Problem. You can find the problem here. The goal is to find the largest decimal number res. Obviously when we obtain a value less than m we should print "not found" since is not a valid solution. Also, when x equals 0 or 100 the problem does not have a solution and these two cases are treated separately. Another problem occurs when 100*( m. Could be much larger than. For large values of. Here is my AC source code:. UVA pr...

3

A programmer's blog: UVA problem 11727 - Cost Cutting

http://roprogrammer.blogspot.com/2010/02/uva-problem-11727-cost-cutting.html

Tuesday, February 2, 2010. UVA problem 11727 - Cost Cutting. I think this is the easiest problem I've ever solved at UVA. You can find the description here. Just read the numbers, sort them and choose the one in the middle. Define SWAP(a, b, c) { c = a; a = b; b = c; }. Int nNoCases, nCaseLoop, nSal1, nSal2, nSal3, nAux;. Scanf("%d", &nNoCases);. For (nCaseLoop = 1; nCaseLoop = nNoCases; nCaseLoop ) {. Scanf("%d %d %d", &nSal1, &nSal2, &nSal3);. SWAP(nSal1, nSal2, nAux);. SWAP(nSal1, nSal3, nAux);.

4

A programmer's blog: ProjectEuler Problem 70 - Investigate values of n for which phi(n) is a permutation of n

http://roprogrammer.blogspot.com/2010/02/projecteuler-problem-70-investigate.html

Saturday, February 6, 2010. ProjectEuler Problem 70 - Investigate values of n for which phi(n) is a permutation of n. Another ProjectEuler task. You can find the description here. I am not proud of my solution, it's just a brute force approach and need a few minutes to print the solution to the screen. I'll try to implement and post a better solution tomorrow. Def Totient(n, PrimeList):. D = primes.Factorization(n, PrimeList);. Numerator, Denominator = n, 1;. For j in d.keys():. Numerator *= j - 1;.

5

A programmer's blog: UVA problem 11743 - Credit Check

http://roprogrammer.blogspot.com/2010/02/uva-problem-11743-credit-check.html

Wednesday, February 3, 2010. UVA problem 11743 - Credit Check. Another very easy UVA problem. You can find the description here. Define MAX LINE LEN 32. Int nNoCases, nCaseLoop, nSumDoubled, nSumUndoubled, nAux;. Char szLine[MAX LINE LEN];. Sscanf(gets(szLine), "%d", &nNoCases);. For (nCaseLoop = 1; nCaseLoop = nNoCases; nCaseLoop ) {. NSumUndoubled = szLine[1] szLine[3] szLine[6] szLine[8] szLine[11] szLine[13] szLine[16] szLine[18] - '0' * 8;. NSumDoubled = 0;. NAux = 2 * (szLine[0] - '0');. View my co...

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A programmer's blog

Wednesday, February 10, 2010. ProjectEuler Problem 179 - Consecutive positive divisors. You can find the problem description here. My Python solution needs some minutes to produce the right answer. Right now i do not know how to optimize it. Max = 10 * 7;. Def bk(Number, NumDivs, CurrentPrimeIndex, PrimeList, List):. If len(List) = NumDivs:. For i in range(len(List), NumDivs 1):. For i in range(CurrentPrimeIndex, len(PrimeList) :. J, pow = 1, PrimeList[i];. N = Number * pow;. If j = 1:. Lists = [];.

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